27y^2+36y-63=0

Solution for 27y^2+36y-63=0 equation:

27y^2+36y-63=0

a = 27; b = 36; c = -63;
Δ = b2-4ac
Δ = 362-4·27·(-63)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-90}{2*27}=\frac{-126}{54}
=-2+1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+90}{2*27}=\frac{54}{54}
=1
$